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Keywords: intcontrol(1005,
Because these actions might take some time, I also implemented a little progress-box with a "percentage complete"-bar.
Although WinBatch is fairly quick (It's the only application running at that time) it might take more than 20 seconds to complete these tasks. Windows 95 then, after those 20 seconds of shut-down mode, unconditionally restarts. This is what I want to prevent.
I Tried using
IntControl (12,10,"Msg",0,0)which does work in "normal"-mode, but Windows 95 doesn't seem to care about this at all at shut-down time.
So, is there a way to prevent Windows 95 from unconditionally rebooting/restarting after 20 seconds of Shut-Down mode?
I'm guessing here, but you might be able to run TWO winbatch scripts at startup.
One script has the IntControl 1005 in it, and the other has the IntControl 12. Something like:
;Script 2 is simple - it stops the shutdown process. BoxTitle("Reboot Preventer") WinHide("") ; only add this AFTER everything is debugged IntControl(12,2,0,l0,0) While 1 TimeDelay(300) endwhile ; It will NEVER terminate by itself.Then in the 1005 script, when you are complete, do a:
;Script 1 is your IntControl 1005 script. It will start processing. ;When it *is* ready to shutdown it uses IntControl 47 to shoot script #2, ;then issues a IntControl 66 67 68 (or something) to complete the shutdown process. IntControl(47,"Reboot Preventer") TimeDelay(2) IntControl(67,0,0,0,0)The theory is (in NT (or was it 95?) at least) Script 1 will start processing and then script 2 will stop the shutdown process. Then Script 1 will have all the time it wants, and then it shoots script 2, then initiates another shutdown.
Article ID: W13317
Filename: Prevent Automatic Reboot after 20 Second Shutdown.txt
File Created: 1999:04:15:16:53:12
Last Updated: 1999:04:15:16:53:12