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DLLCALL: Float as a passed param to DLLCALL
Keywords: floating point numbers and DLLCall
Question:
Is there an example of how to pass a float to a DLL?I have many Dlls that I would like to pass a single (or a couple) floats to and have been unsuccessful, in an example as simple as:
=======DLL==========
float WINAPI MyFloatFunc(float PassedFloat)
{
PassedFloat = 10.0 + PassedFloat;
return PassedFloat;
}
=======WBT==========
myfloat=1.123
a1=DllCall("mydll.dll", long:"MyFloatFunc",long:myfloat)
Message("Returned a Value","MyFloatFunc returned %a1%")
a1 gets printed as: "1240488"
When I print out the value PassedFloat from inside the DLL,(after sprintf %f into a string and printing with MessageBox) it prints a "0.00000".
What did I miss? What is the proper parameter type for a simple FLOAT?
Answer:
EEEKNo direct support for Float. However it is possible to do by changing your routines. Something like this TOTALLY UNDEBUGGED CODE.
void WINAPI MyFloatFunc(DOUBLE * PassedFloat, DOUBLE * AsnwerFloat)
{
*AnswerFloat = 10.0 + *PassedFloat;
return;
}
Then in WinBatch
;add 10.0 to zorkfloat
zorkfloat=123.45
pass=BinaryAlloc(8)
ans=BinaryAlloc(8)
BinaryEODSet(ans,8)
BinaryPokeFlt(pass,0,zorkfloat)
DllCall("your.dll",void:"MyFloatFunc",lpbinary:pass,lpbinary:ans)
zorkplus10=BinaryPeekFlt(ans,0)
Message(zorkfloat,zorkplus10)
;----------
Article ID: W12869
Filename: Float as a passed param to DLLCALL.txt
File Created: 1999:04:15:16:50:12
Last Updated: 1999:04:15:16:50:12